-3*x^2-5*x-3=6*x+7

Solution for -3*x^2-5*x-3=6*x+7 equation:

-3x^2-5x-3=6x+7

We move all terms to the left:

-3x^2-5x-3-(6x+7)=0

We get rid of parentheses

-3x^2-5x-6x-7-3=0

We add all the numbers together, and all the variables

-3x^2-11x-10=0

a = -3; b = -11; c = -10;
Δ = b2-4ac
Δ = -112-4·(-3)·(-10)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*-3}=\frac{10}{-6}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*-3}=\frac{12}{-6}
=-2
$